Friday, February 26, 2010

PROBLEM:

Given:
Z = no. of coils = 15 coils
P = no. of poles = 2 poles

# of conductors = 15 x 2 = 30 elements

Progressive lap winding
YB = (Z/P)+1=(30/2)+1=16approx.17

Use: YB = 17 since should always odd #
YB & YF = odd #’s
YB & YF = should differ each other by 2
Since YB = 17 then YF =15
Note*: YF should less than YB for progressive commutator pitch YC=1
No. of commutator segments = no. of coils
YC = +1
Winding Table
1 – 18 – 3 – 20 – 5 – 22 – 7 – 9 – 26
11 – 28 – 13 – 15 – 2 – 17 – 4 – 19
6 – 21 – 8 – 23 – 10 – 25 – 12 – 29 -27
17 – 29 – 16 – 1

SIMPLEX WAVE WINDING DESIGN
1. Both pitcher YB & YF are odd numbers.
2. Back and Front Pitcher are nearly equal to the pole pitch and maybe equal or differ by 2.
3. Resultant Pitch (YR = YB + YF )
4. Commutator Pitch YC = YA
5. The average pitch which must be an integer is given by YA =
Given:
No. of poles = 4
No. of coils = 15

Design a simplex wave winding progressive.

YB = (30+2)/4
YB = 8 approx. 9
YA = YB

for progressive type :
YB > YF
for retrogressive type :
YB < YF

YC = YA = YF

YC = 1 – 8 – 15 – 7 – 14 – 6 – 13 – 5 – 12 – 4 – 11 – 3 – 10 – 2 – 9

Winding Table
1 – 10 – 17 – 26 – 3 – 2 – 19 – 28 – 5 – 14 – 21 – 30
7 – 16 – 23 – 2 – 9 – 18 – 25 – 4 – 11 – 20 – 27 – 6 – 13
29 – 8 – 15 – 24 – 1

When:
YB = YF

1 – 8 – 15 – 22 – 29 – 6 – 13 – 20 – 27 – 4 – 11 – 18 – 25
2 – 9 – 16 – 23 – 30 – 7 – 14 – 21 – 28 – 5 – 12 – 19 – 26
3 – 10 – 17 – 24 - 1





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